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![Why is u-substitution the reverse chain rule? Furthermore, why do we differentiate rather then antidifferentiate when we perform the substitution? So for the step from u = g(x) to du = g'(x)dx. : Why is u-substitution the reverse chain rule? Furthermore, why do we differentiate rather then antidifferentiate when we perform the substitution? So for the step from u = g(x) to du = g'(x)dx. :](https://preview.redd.it/why-is-u-substitution-the-reverse-chain-rule-furthermore-v0-6xg2sol9dyyb1.jpg?width=640&crop=smart&auto=webp&s=da8255d67f94004b18f7031d7fadde4309497f86)
Why is u-substitution the reverse chain rule? Furthermore, why do we differentiate rather then antidifferentiate when we perform the substitution? So for the step from u = g(x) to du = g'(x)dx. :
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